9x^2+8x=17

Solution for 9x^2+8x=17 equation:

9x^2+8x=17

We move all terms to the left:

9x^2+8x-(17)=0

a = 9; b = 8; c = -17;
Δ = b2-4ac
Δ = 82-4·9·(-17)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-26}{2*9}=\frac{-34}{18}
=-1+8/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+26}{2*9}=\frac{18}{18}
=1
$